关于C语言下EEPROM的读写问题

winnie

我用的是PIC16F877A单片机，仿真器是高奇的picmate2002，现在欲验证下写进去的数据和读出来的数据是不一样，特意编写如下程序，可是程序编译成功了，但不论写入何数据，读出来的数据都是00，这是什么原因啊？难道没写进去？程序如下，望大虾们帮忙看看，多谢，急啊！
#include   <pic.h>
unsigned char eeprom_read(unsigned char addr);
void eeprom_write(unsigned char addr,unsigned char value);
void eeprom_write(unsigned char addr,unsigned char value)
{
EEADR=addr;
EEDATA=value;
EEPGD=0;
WREN=1;
EECON2=0x55;
EECON2=0xaa;
WR=1;
do {;}
while(WR==1);
  WREN=0;//写保护
}
unsigned char eeprom_read(unsigned char addr)//片内EEPROM的读取
{
unsigned char rd_data;
EEADR=addr;
EEPGD=0;
RD=1;
rd_data=EEDATA;//读取EEDATA的内容
return(rd_data);
}
main()
{
   unsigned  char  data1,data2;
   unsigned  char  address;
   address=0x80;
   data1=0x50;
   eeprom_write(address,data1);
   data2=eeprom_read(address);
NOP();
}

winnie

内存调用是这样的!
#include   <pic.h>


void eeprom_write(unsigned char address,unsigned char datavalue)
{
asm("CLRWDT");
eeprom_write(address,datavalue);
while(WR == 1)
{
  asm("CLRWDT");
}
}

unsigned char eeprom_read(unsigned char address)
{
return EEPROM_READ(address);
}

main()
{
   unsigned  char  data1,data2;
   unsigned  char  address;
   address=0x80;
   data1=0x50;
   eeprom_write(address,data1);
   data2=eeprom_read(address);
}